four times a number and three times another number added together make 43. Two times the second number, subtracted from three times the first gives 11. What are the numbers?
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Answered by
2
Answer:
Step-by-step explanation:
Supposed first number is X.
And another number is Y.
By first condition,
4X+3Y=43…. (1)
By second condition,
3X-2Y=11……(2)
Multiplying first by 2 and second by 3.
8X+6Y=86
+9X-6Y=33
We get, 17X=119
I. E. X=119/17
X=7
Substitute X=7 in equation 1 st .
28+3Y=43
3Y=43–28
3Y=15
Y=5.
This number are (7,5) .
Answered by
10
Heyy mate, here is your answer
Supposed first number is X.
And another number is Y.
By first condition,
4X+3Y=43…. (1)
By second condition,
3X-2Y=11……(2)
Multiplying first by 2 and second by 3.
8X+6Y=86
+9X-6Y=33
17X=119
i. e, X=119/17
X=7
Substitute X=7 in equation 1 st .
28+3Y=43
3Y=43–28
3Y=15
Y=5.
This number are 7 and 5
hope helps✌✌
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