Four times the area of the curved surface of a cylinder is equal to 6 times the sum of the areas of its bases . If its height is 12cm , then find its curved surface area .
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Curved Surface Area= 2πrh sq.cm
Area of the base = πr² sq.cm.
Sum area of the base= πr²+πr²= 2πr²sq.cm
A.T.Q
4(2πrh)= 6×2πr²
8πrh=12πr²
2h=3r
2×12=3r
r=8cm.
Curved Surface Area=2πrh
= 2×22/7×8×12
=4224/7
= 603.42 sq.cm
Area of the base = πr² sq.cm.
Sum area of the base= πr²+πr²= 2πr²sq.cm
A.T.Q
4(2πrh)= 6×2πr²
8πrh=12πr²
2h=3r
2×12=3r
r=8cm.
Curved Surface Area=2πrh
= 2×22/7×8×12
=4224/7
= 603.42 sq.cm
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