Math, asked by syk786, 7 months ago

Varun took a loan of ruppees 80,000 from a bank. If the rate of interest is 10 percent per annum find the difference in amounts he would be paying after 1 1/2 years if the interest is
compounded annually
compounded half yearly​

Answers

Answered by Anonymous
11

Solution :

Compounded annually

  • P = Rs 80,000

  • R = 10% per annum

  • n = 1½ year

the amount for 1 year and 6 months can be calculated by first calculating the amount for year using the compound interest formula, and then calculating the simple interest for 6 months on the amount obtained at the end of 1 year.

First, the amount for 1 year has to be calculated.

Amount, A = P(1 + R/100)^n

=80000 (1 + 10/100)¹

= 80000 x 11/100

= Rs 88000

By taking 88,000 as principal, the Sl for the next ½ year wil be calculated.

I = P x R x T/100

= 88000 x 10 x ½/100

= Rs 4400

Interest for the first year = Rs 88000 - Rs 80000 = Rs 8,000

And interest for the next ½ year = Rs 74,400

Total C.I. = 8000 + 4,400 +

= Rs 12400

A = P + C.l

= Rs (80000 + 12400)

= Rs 92,400

The interest is compounded halt yearly.

Rate = 10% per annum = 5% per halfyear

There will be three half years in 1 ½ years.

Amount, A = P(1 + R/100)^n

=Rs 80000(1 + 10/100)^³

= Rs 80000 x (105/100)³

= Rs 92610

Difference between the amounts

= Rs 92,610 - Rs 92,400

= Rs 210

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