Question

Four times the first of three consecutive odd integers is 6 more than twice the third. the third integer is

Answer 1

Let the three consecutive odd no. Be x+1,x+2and x+3
a.t.c.
4(x+1+x+2+x+3)=2(x+3)
4(3x+6)=2(x+3)
12x+24=2x+6
10x=-18
X=-1.8

Answer 2

Answer:

11

Step-by-step explanation:

Let the three consecutive odd integers be x+1,x+3,x+5

We are given that Four times the first of three consecutive odd integers is 6 more than twice

⇒4(x+1)=6+2(x+5)

⇒4x+4=6+2x+10

⇒4x-2x=6-4+10

⇒2x=2+10

⇒2x=12

⇒x=12/2

⇒x=6

So , third integer = x+5=6+5=11