Question

Four times the square of a number is
45 more than the eight times of the
number. What is the number?​

Answer 1

Step-by-step explanation:

let the no. be x

4x^2=45+8x

or, 4x^2-8x-45=0

Answer 2

SOLUTION;

LET US, ASSUME THE NUMBER BE X .

THEN , ACCORDING TO GIVEN CONDITION ,WE GET;

=>. 4 × (X) ^2 =. 45 + 8(X)

THEN, BY REARRANGING THE EQUATION, WE GET ;

=>. 4X^2. = 45 + 8X

=>. 4X ^2. - 8X. - 45 = 0 ....(1)

SO ,WE GET A QUADRATIC EQUATION (2) .

NOW ,BY FACTORISING THE QUADRATIC EQUATION ;

=>. 4X^2. - 8X. - 45

=>. 4X^2. - 18 X. + 10 X - 45

=>. 2X. ( 2X -. 9) +. 5 (2X - 9)

=>. (2X + 5 ) ( 2X - 9)

BY PUTTING ( 2X - 9) = 0 ;

SO,THE NUMBER REQUIRED IS 9/2 .

HOPE IT HELPS YOU FRIEND .