Four unpaired electron are present in -a) Fe2+ b) Ni2+ c) Mn2+ d)Fe3+ what is the answer ?
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Answer would be @) Fe 2+
It's configuration is 3s² 3p6 3d6 and thus 4 electrons are unpaired.
It's configuration is 3s² 3p6 3d6 and thus 4 electrons are unpaired.
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