Physics, asked by Sneha1021, 1 year ago

Four wires of equl length and of resistances 10 ohm each aare vonnected in the form of a square. The equivalent resistance between two opposite corners of a square is ?

Answers

Answered by panuj329p1gs45

5 ohm as same current is passing so they are in series.

panuj329p1gs45: think for ur self if i connect 4 resistance by one by one then ...is this not series

saikat1998: two 10 ohm is in series and hence two 20 ohm is in parallel . thus equivalent resistance is (20×20)÷(20+20)=10ohm

panuj329p1gs45: and question is asking for eq. of 2

panuj329p1gs45: 10 ohm is total

panuj329p1gs45: not opposite

panuj329p1gs45: they are not in parallel....

saikat1998: ok. but i think 10 ohm is the answer

Sneha1021: I understand how to do it..... and its ans is 10 ohm for sure

panuj329p1gs45: tell me plz i also want to know

saikat1998: trying to explain. Pls see the answer.

Answered by saikat1998

see the photo.
ABCD is the square which contains 10 ohm resistor at each arm.
There is a connection at A and C end (opposite corner).

Thus, AD and DC are in series(=20 ohm).
and AB and BC are in series(=20 ohm).

again (AD+DC) and (AB+BC) are in parallel.
So if the equivalent resistance between A and C is R then,
1÷R= 1÷20 + 1÷20
or , R= 20×20÷(20+20) ohm
=10 ohm

So, the answer is 10 ohm

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