Four wires of equl length and of resistances 10 ohm each aare vonnected in the form of a square. The equivalent resistance between two opposite corners of a square is ?
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Answered by
1
5 ohm as same current is passing so they are in series.
panuj329p1gs45:
think for ur self if i connect 4 resistance by one by one then ...is this not series
two 10 ohm is in series and hence two 20 ohm is in parallel . thus equivalent resistance is (20×20)÷(20+20)=10ohm
and question is asking for eq. of 2
10 ohm is total
not opposite
they are not in parallel....
ok. but i think 10 ohm is the answer
I understand how to do it..... and its ans is 10 ohm for sure
tell me plz i also want to know
trying to explain. Pls see the answer.
Answered by
9
see the photo.
ABCD is the square which contains 10 ohm resistor at each arm.
There is a connection at A and C end (opposite corner).
Thus, AD and DC are in series(=20 ohm).
and AB and BC are in series(=20 ohm).
again (AD+DC) and (AB+BC) are in parallel.
So if the equivalent resistance between A and C is R then,
1÷R= 1÷20 + 1÷20
or , R= 20×20÷(20+20) ohm
=10 ohm
So, the answer is 10 ohm
ABCD is the square which contains 10 ohm resistor at each arm.
There is a connection at A and C end (opposite corner).
Thus, AD and DC are in series(=20 ohm).
and AB and BC are in series(=20 ohm).
again (AD+DC) and (AB+BC) are in parallel.
So if the equivalent resistance between A and C is R then,
1÷R= 1÷20 + 1÷20
or , R= 20×20÷(20+20) ohm
=10 ohm
So, the answer is 10 ohm
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