Math, asked by ajayyadavroxx90, 1 year ago

four year ago the ratio of A and B was 4:5 the present age is in ratio 14:17 .what was B's age before 5 years?​

Answers

Answered by spiderman2019
0

Answer:

29 yrs.

Step-by-step explanation:

Let x and y be the present ages of A & B.

x/y = 14/17

17x - 14y = 0  -----------> equation 1

x-4/y-4 = 4/5

5x - 20 - 4y+16 = 0

5x - 4y = 4  ----------------> equation 2

//multiply equation 2 by 7/2 and subtract equation 1 from equation 2.

35/2x  - 14y  = 14

17x      -  14y  = 0

-------------------------

(35/2 - 17) x - 0y = 14

x/2 = 14

x = 28 yrs.

//substitute in x/y = 14/17

=> y = 34 yrs

So B's age before 5 years = 34 - 5 = 29 yrs.

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