Question

Four years ago, 1/3rd of A's age and nine times B's age were in the ratio 8:27. Seven years hence 1/5th of A's age is equal to the present age of B. What is B's present age?
1)7years 2)5years 3)9years 4)6 years 5)nine

Answer 1

Sorry I m not getting but I tried.

Answer 2

Step-by-step explanation:

Let A's present age = x and B's present age = y.

4 years ago:

1/3rd of A's age and nine times B's age were in the ratio 8:27.

⇒ [(x/3 - 4)]/(9y - 4] = 8/27

⇒ (x - 12)/3(9y - 4) = 8/27

⇒ 27x - 324 = 8(27y - 12)

⇒ 27x - 324 = 216y - 96

⇒ 27x - 216y = 228

⇒ 9x - 72y = 76       -------- (1)

Seven years hence 1/5th of A's age is equal to the present age of B.

(1/5 x) + 7 = y + 7

⇒ x + 35 = 5y + 35

⇒ x - 5y = 0

⇒ x = 5y

Place x = 5y in (1), we get

⇒ 9x - 72y = 76

⇒ 9(5y) - 72y = 76

⇒ 45y - 72y = 76

Cannot be Solved..  Seems like Question is incorrect!