four years ago a father was nine times as old as his son, and 8 years hence the father's age will be three times the son's age. find their present ages.
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Step-by-step explanation:
let the father's age be 4x and son's age be x
after 10years
4x + 10 = 3 *(x+ 10)
4x+10= 3x +30
4x -3x = 30-10
x= 20
therefore father's present age = 4x
=4 * 20 = 80
son's present age = x=20
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