Four years ago, a man was three times as old as his son, and 6 years hence,
the man will only be twice. The son’s present age is
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0
Answer:
I don't know
Step-by-step explanation:
I really don't know
Answered by
0
Answer:
Son present age = 12
father present age = 24
Step-by-step explanation:
Four years ago:-
let son age = x
father age = 3x
6 years later:-
son age = x+6
father age = 3x+6
it is given that father age is twice as son after six years,
So,
2(x+6)=3x+6
2x+12=3x+6
12-6=3x-2x
6=x
x=6
Son present age = x+6 = 6+6 = 12
father present age = 3x+6 = 3×6+6=18+6=24
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