Math, asked by marshalmurmu734, 1 month ago

Four years ago, a man was three times as old as his son, and 6 years hence,
the man will only be twice. The son’s present age is​

Answers

Answered by asthaparmar59
0

Answer:

I don't know

Step-by-step explanation:

I really don't know

Answered by NITESH761
0

Answer:

Son present age = 12

father present age = 24

Step-by-step explanation:

Four years ago:-

let son age = x

father age = 3x

6 years later:-

son age = x+6

father age = 3x+6

it is given that father age is twice as son after six years,

So,

2(x+6)=3x+6

2x+12=3x+6

12-6=3x-2x

6=x

x=6

Son present age = x+6 = 6+6 = 12

father present age = 3x+6 = 3×6+6=18+6=24

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