Question

Four years ago Marina was three times old as her daughter. Six years from now the
mother will be twice as old as her daughter. Find their present ages.​

Answer 1

sorry I didn't have answer

Answer 2

Answer:

34 , 14

Step-by-step explanation:

Let take the present age of Marina as x years and

The present age of Marina’s daughter as y years.

Now, four years ago

Age of Marina will be (x – 4) years

Age of Marina’s daughter will be (y – 4) years

According to the first condition given in the problem, we have

(x – 4) = 3 (y – 4)

x – 4 = 3y – 12

x – 3y = -8 … (i)

Now, the age of Maria after 6 years will be (x + 6) years

And the age of Maria’s daughter will be (y + 6) years

Then, according to the second condition given in the problem, we have

x + 6 = 2 (y + 6)

x + 6 = 2y + 12

x – 2y = 6 … (ii)

From equations (i) and (ii), we get

x – 2y = 6

x – 3y = -8

(-)—(+)—(+)

y = 14

On substituting the value of y in (i), we get

x – 3 x 14 = -8

x – 42 = -8

x = -8 + 42

x = 34

Therefore, the age of Marina is 34 years and the age of her daughter is 14 years.