four years ago my father's age was 4 times that of my age. at present, the sum of my father's age and that of mine is 53 years. what is my father's present age?
Answers
Answered by
95
Let your age four years ago be x
then four years ago your father's age=4x
after four years your age=x+4
after four years your father's age=4x+4
Equation is
53=(x+4)+(4x+4)
53=5x+8
x=9
then four years ago your father's age=4x
after four years your age=x+4
after four years your father's age=4x+4
Equation is
53=(x+4)+(4x+4)
53=5x+8
x=9
shayani13:
thank you so much
Answered by
21
Answer: My age = 13; Father's age = 40
Step-by-step explanation:
Four year ago,
my age=x
Father's age= 4x
present
my=x+4
father's age=4x+4
According to the question
x+4+4x+4=53
5x+8=53
x=9
present age= x+4=9+4=13
Father's age = 4(9)+4=40
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