Math, asked by shayani13, 1 year ago

four years ago my father's age was 4 times that of my age. at present, the sum of my father's age and that of mine is 53 years. what is my father's present age?

Answers

Answered by Dam910
95
Let your age four years ago be x
then four years ago your father's age=4x
after four years your age=x+4
after four years your father's age=4x+4
Equation is
53=(x+4)+(4x+4)
53=5x+8
x=9

shayani13: thank you so much
Dam910: You thank you for making my answer brainliest
Answered by karambirsingh22k
21

Answer: My age = 13; Father's age = 40

Step-by-step explanation:

Four year ago,

my age=x

Father's age= 4x

present

my=x+4

father's age=4x+4

According to the question

x+4+4x+4=53

5x+8=53

x=9

present age= x+4=9+4=13

Father's age = 4(9)+4=40

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