Question

four years ago, rahim age was three times ramu's age. After two years, it would just be double. What are their aged now?

Answer 1

Let Ramu's age be x years old 4 years ago

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STEP 1: Find their age 4 years ago:

4 years ago:

Ramu = x

Rahum = 3x

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STEP 2: Find their age now:

Now:

Ramu = x + 4

Rahim = 3x + 4

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STEP 3: Find their age 2 years later:

Two years later,

Ramu = x + 4 + 2 = x + 6

Rahim = 3x + 4 + 2 = 3x + 6

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STEP 4: Form equation and solve for x:

Rahum's age will be double of Ramu:

3x + 6 = 2(x + 6)

3x + 6 = 2x + 12

x = 6

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STEP 5: Find their age:

Present age:

Ramu = x + 4 = 6 + 4 = 10 years old

Rahim = 3x + 4 = 3(6) + 4 = 22 years old

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Answer: Ramu is 10 years old and Rahim is 22 years old

Answer 2

Hey mate here is ur query..
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Assume present Rahim's age =x
& Ramu's age=y

4 years ago...

x-4 =3 (y-4)----------1.

or x-3y=-8

After 2 years
x+2 = 2{y+2}

or x-2y =2-----------2.

solving both equation

x=22
y=10

i.e
Rahim present age=22
Ramu present age=10
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Hope this will help you..