Question

the ages of two girls are in the ratio 5:7 eight years ago their ages were in the ratio 7:13

Answer 1

Let the present age of the first girl be 5x and the second girl be 7x.

Now,

there ages 8 yrs ago = (5x-8) / (7x-8) = 7/13

65x - 104 = 49x - 56

16x = 48

x=3

The age of the first girl = 5×3 = 15 yrs

The age of the second girl = 7×3 = 21 yrs.

Answer 2

Here is your answer dear⬇️⬇️



Let the ages be 5x and 7x

Eight years ago ages be

$\frac{5x-8}{7x-8}$ = $\frac{7}{13}$

65x - 104 = 49x - 56

65x - 49x = 104 - 56

16x = 48

x = $\frac{48}{16}$

x = 3



$\therefore{}$ The age of first girl = 5x = 5 × x = 5 × 3 = $15$


$\therefore{}$ The age of second girl = 7x = 7 × x = 7 × 3 = $21$