Four years ago, Rahim's age was three times Ramu's age. After two
years, it would just be double. What are their ages now?
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Answer:
Step-by-step explanation:
let rahim's present age be x
ramu's present age =y
4 yrs ago ,
rahim's age =x-4
ramu's age=y-4
x-4=3{(y-4)}
x-4=3y-12
x=3y-8
2 years later,
rahim's age =x+2
ramu's age=y+2
x+2=2[(y+2)]
3y-8+2=2y+4
y=10 years
x=3y-8
x=30-8
x=22 years
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