Question

Fourth ionization potential of be3+ from the second excited state is

Answer 1

The energy of a 1 lepton atom or particle in a very given quantum state is (to a primary approximation) proportional to the sq. of the nuclear charge, Z^2. The ionization energy is additionally proportional to Z^2, since that's the distinction between the bottom state of the atom/ion and therefore the energy of the separated particle and lepton.

The charge of Be^(4+) is fourfold that of H^+, therefore the ionization energy of Be^(3+) is 4^2 or sixteen times that of H.