Question

fourth term of an A.P is ten times the first prove that six term is four times as great as second term .​

Answer 1

Answer:

hey here is your solution

so pls mark I as brainliest pls

Step-by-step explanation:

To Prove:a+5d=4(a+d)

now let the first term of an ap be a and that of fourth term be a+3d

Moreover let the six term be a+5d and second term be a+d

so according to given condition

a+3d=10a

ie 3d=9a

so d=3a

now substitute this value in to prove part

we obtain

a+5d=4(a+d)

ie a+(5×3a)=4(a+3a)

so a+15a=4×4a

ie 16a=16a

hence lhs=rhs

thus proved

Answer 2

Answer:

hard workers have less followers sis..

it's ok keep trying..

you will get many followers❤