Math, asked by rkdeep2779, 10 months ago

\frac { 1 } { x } - \frac { 1 } { x - 2 } = 3 ( x \neq 0,2 )​

Answers

Answered by Anonymous
7

Answer:

x = (3+√3) / 3 , (3-√3) / 3

Step-by-step explanation:

We have

(1/x) - [1/(x-2)] = 3

Then,

1 1

=> --- - ------ = 3

x x - 2

The common denominator is x(x-2)

Thus =>

1 x-2 1 x

---• ----- - ----- • --- = 3

x x-2 x-2 x

x-2 x

=> ------- - ------- = 3

x(x-2) x(x-2)

x-2 - x

=> -------- = 3

x(x-2)

=> -2 = 3x(x-2)

=> -2 = 3x2-6x

=> 3x^2 - 6x + 2 = 0

Using the quadratic formula we can solve for x,

-b±√(b2-4ac)

--------------

2a

6±√[62-4(3)(2)]

=> -----------------------

2(3)

6±√(36-24)

=> ------------------

6

6±√12

=> ------------

6

6±2√3

=> -------------

6

3±√3

=> ----------

3

Hence, the values of x are :

x = (3+√3) / 3 , (3-√3) / 3

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