Question

fractorization of 4x²-16x+7​

Answer 1

Answer:

4x²-16x+7 = 0

4x²-(14+2)+7 = 0

4x²-14x-2x+7 = 0

2x(2x-7)-1(2x-7) = 0

(2x-1) (2x-7)

Answer 2

Given:

• $\sf{Factorization of 4x^2-16x+7}$

To find:

• Factors

Solution:

$: \implies \sf{ {4x}^{2} - 16x + 7}$

$: \implies \sf{ {4x}^{2} -2x - 1 4x + 7}$

$: \implies \sf{ 2x(2x - 1) - 7(2x - 1)}$

$: \implies \underline{ \boxed{ \frak{ (2x - 1) (2x - 7)}}} \pink \bigstar$

• Hence, the answer is (2x-1)(2x-7)

тнαηк үσυ

@itzshivani