Math, asked by Sushma12391, 1 year ago

Frame and solve the equation.
TWO NUMBERS ARE IN THE RATIO 5:3 ff THEY ARE DIFFER BY 18.
WHAT IS THE NUMBER?


URGENT PLEASE​

Answers

Answered by Anonymous
3

Answer:

45 and 27

Step-by-step explanation:

Let the common ratio be x

Two numbers are 5x and 3x.  

According to given condition,

5x - 3x= 18  

2x = 18

x = 9

Then:

1st number = 5(9) = 45

2nd number = 3(9) = 27

Thus, the numbers are 45 and 27

Answered by deepsen640
10

HELLO DEAR FRIEND

given ratio of numbers = 5:3

difference = 18

so,let the number be 5x and 3x

ATQ,

5x - 3x = 18

2X = 18

 \large{ x = \frac{ \large{18}}{ \large{2}} }

 \large \boxed{x =  \:  \boxed{9}}

numbers are 3x = 3 × 9 =

 \large{27}

and 5x = 5 × 9 =

 \large{45}

so, the numbers are

 \large \boxed{ \boxed{27} \:  \:  \:  \:  \:  \: and\:  \:  \:  \:  \:  \:  \boxed{45}}

THANKS

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