Frame the equation in two variable for following statement. "The length of rectangle is two more than its breadth. The perimeter of rectangle is 36cm."
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Answered by
0
LET THE BREADTH OF THE RECTANGLE BE 'X'
SO, BY GIVEN CONDITION
LENGTH OF RECTANGLE IS ' X+2'
WE KNOW THAT PERIMETER OF A RECTANGLE IS 2(LENGTH + BREADTH)
BY USING THE VALUES OF GIVEN CONDITION ,
PERIMETER OF RECTANGLE= 2(X+2+X)
= 2(2X+2)=4X+4
SO, BY GIVEN CONDITION
LENGTH OF RECTANGLE IS ' X+2'
WE KNOW THAT PERIMETER OF A RECTANGLE IS 2(LENGTH + BREADTH)
BY USING THE VALUES OF GIVEN CONDITION ,
PERIMETER OF RECTANGLE= 2(X+2+X)
= 2(2X+2)=4X+4
Answered by
1
HEY DEAR_____❤❤❤❤❤
HERE IS THE ANSWER:-)
=>Let the length be € and breadth be ¥.
=>According to question,
=> (Length) = breadth + 2
=> € - ¥ = 2 or € = ¥ + 2 cm -----------(equation 1)
#PERIMETER OF RECTANGLE
=> 2(Length + breadth) = 36 cm
=> 2( € + ¥ ) 36
=> € + ¥ = 36/2
=> € + ¥ = 18 cm -----------(equation 2)
#FROM EQUATION 1 PUT THE VALUE OF € IN EQUATION 2
=> (¥ + 2 ) + ¥ = 18
=> ¥ + ¥ + 2 = 18
=> 2¥ = 18 - 2
=> 2¥ = 16
=> ¥ = 16/2
=> ¥ = 8 cm
PUT THE VALUE OF ¥ IN EQUATION 1
=> € = ¥ + 2
=> € = 8 + 2
=> € = 10 cm
SO,length = 10 cm and breadth = 8 cm.
HOPE IT WILL HELP YOU..
❤❤❤❤❤❤❤❤❤
@AKJORDAN1
HERE IS THE ANSWER:-)
=>Let the length be € and breadth be ¥.
=>According to question,
=> (Length) = breadth + 2
=> € - ¥ = 2 or € = ¥ + 2 cm -----------(equation 1)
#PERIMETER OF RECTANGLE
=> 2(Length + breadth) = 36 cm
=> 2( € + ¥ ) 36
=> € + ¥ = 36/2
=> € + ¥ = 18 cm -----------(equation 2)
#FROM EQUATION 1 PUT THE VALUE OF € IN EQUATION 2
=> (¥ + 2 ) + ¥ = 18
=> ¥ + ¥ + 2 = 18
=> 2¥ = 18 - 2
=> 2¥ = 16
=> ¥ = 16/2
=> ¥ = 8 cm
PUT THE VALUE OF ¥ IN EQUATION 1
=> € = ¥ + 2
=> € = 8 + 2
=> € = 10 cm
SO,length = 10 cm and breadth = 8 cm.
HOPE IT WILL HELP YOU..
❤❤❤❤❤❤❤❤❤
@AKJORDAN1
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