frame this equation and solve
The length of the rectangle is twice its breadth. If the perimeter is 18cm. Find its length and
breadth.
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HEY BUDDY..!!!
HERE'S THE ANSWER..
_____________________
▶️Let the length of rectangle be ( x )
▶️Let the breadth of rectangle be ( y )
♠️ Length of rectangle is twice of breadth , i.e
=> length = 2 × breadth
=> x = 2 . y
=> x - 2 y = 0 _________( 1 )
⏺️ Now perimeter is 18 cm
=> 2 ( length + breadth )
=> 2 ( x + y ) = 18
=> x + y = 9 ___________( 2 )
♠️ From Eqn ( 1 )
=> x - 2 y = 0
=> x = 2 y ✔️
⏺️ Putting value of x in Eqn ( 2 )
=> x + y = 9
=> 2 y + y = 9
=> 3 y = 9
=> [ y = 3 cm ]✔️✔️
⏺️Now putting value of y in eqn ( 1 )
=> x - 2 y = 0
=> x = 2 y
=> x = 2 ( 3 )
=> [ x = 6 cm ] ✔️✔️
♠️ So length of rectangle is { 6 cm } and breadth of rectangle is { 3 cm } .
HOPE HELPED..
JAI HIND..
:-)
HERE'S THE ANSWER..
_____________________
▶️Let the length of rectangle be ( x )
▶️Let the breadth of rectangle be ( y )
♠️ Length of rectangle is twice of breadth , i.e
=> length = 2 × breadth
=> x = 2 . y
=> x - 2 y = 0 _________( 1 )
⏺️ Now perimeter is 18 cm
=> 2 ( length + breadth )
=> 2 ( x + y ) = 18
=> x + y = 9 ___________( 2 )
♠️ From Eqn ( 1 )
=> x - 2 y = 0
=> x = 2 y ✔️
⏺️ Putting value of x in Eqn ( 2 )
=> x + y = 9
=> 2 y + y = 9
=> 3 y = 9
=> [ y = 3 cm ]✔️✔️
⏺️Now putting value of y in eqn ( 1 )
=> x - 2 y = 0
=> x = 2 y
=> x = 2 ( 3 )
=> [ x = 6 cm ] ✔️✔️
♠️ So length of rectangle is { 6 cm } and breadth of rectangle is { 3 cm } .
HOPE HELPED..
JAI HIND..
:-)
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Answer:
The length of the rectangle is twice the breadth. Its perimeter is 18 cm. Then its length and breadth are __________. *
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