Question

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Answer 1

Answer:

Sec(A+B) = Sec(90°) = Indefinite (Not Defined)

Explanation:

Here, <C = 90°

Here, <C = 90°We, know that sum of interior angles of Triangle = = 180°

Here, <C = 90°We, know that sum of interior angles of Triangle = = 180°So, <A+<B+<C = 180°

Here, <C = 90°We, know that sum of interior angles of Triangle = = 180°So, <A+<B+<C = 180°=> <A+<B+90° = 180°

Here, <C = 90°We, know that sum of interior angles of Triangle = = 180°So, <A+<B+<C = 180°=> <A+<B+90° = 180°=> <A+<B = 180°-90° = 90°

Here, <C = 90°We, know that sum of interior angles of Triangle = = 180°So, <A+<B+<C = 180°=> <A+<B+90° = 180°=> <A+<B = 180°-90° = 90°So, Sec(A+B) = Sec(90°) = Indefinite (Not Defined)

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Answer 2

Explanation:

As we know that,In triangle ABC

<A+<B+<C = 180° [But the triangle is right angled at C] ::GIVEN.

i.e,<C = 90°

;<A+<B+90° =180°

=> <A+<B =90°

; Cos (A+B) = Cos 90° = 0