Free coins are tossed together find the probability of getting exactly two head at least two head at least two tail
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Answer:
s={HHH,HTH,HTT,TTT,THT,THH}
n(s)=6
Step-by-step explanation:
event a=getting exactly 2 head
A={HTH,THH}
n(a)=2
p(a)=n(a)\ n(s)=2\6=1\3
event b=at least 2 head
B={HHH,HTH,THH}
n(b)=3
p(b)=n(b)\ n(s)=3\6=2
event c=at least 2 tail
C={HTT,TTT,THT}
n(c)=3
p(c)=n(c)\n(s)=3\6=1\2
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