Question

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maths ch1 pg1.22 Q25 SM

plz explain in detail step by step ​.

Answer 1

ANSWER:

$\bf (c)1$

STEP-BY-STEP VERIFICATION:

$\frac{1}{(1 + {a}^{m - n} + {a}^{m - p} )} + \frac{1}{(1 + {a}^{n - m} + {a}^{n - p} )} + \frac{1}{(1 + {a}^{p - m} + {a}^{p - n} )}$

$= \frac{1}{1 + \frac{ {a}^{m} }{ {a}^{n} } + \frac{ {a}^{m} }{ {a}^{p} } } + \frac{1}{1 + \frac{ {a}^{n} }{ {a}^{m} } + \frac{ {a}^{n} }{ {a}^{p} } } + \frac{1}{1 + \frac{ {a}^{p} }{ {a}^{m} } + \frac{ {a}^{p} }{ {a}^{n} } }$

$= \frac{1}{ {a}^{m} ( \frac{1}{ {a}^{m} } + \frac{1}{ {a}^{n} } + \frac{1}{ {a}^{p} } ) } + \frac{1}{ {a}^{n} ( \frac{1}{ {a}^{n} } + \frac{1}{ {a}^{m} } + \frac{1}{ {a}^{p} } ) } + \frac{1}{ {a}^{p} ( \frac{1}{ {a}^{p} } + \frac{1}{ {a}^{m} } + \frac{1}{ {a}^{n} } ) }$

$= \frac{1}{ ( \frac{1}{ {a}^{m} } + \frac{1}{ {a}^{n} } + \frac{1}{ {a}^{p} } ) } \times ( \frac{1}{ {a}^{m} } + \frac{1}{ {a}^{n} } + \frac{1}{ {a}^{p} } )$

$= 1$

SO, C IS CORRECT.

Answer 2

answer is attached above it is option c ......