freezing point of an aqueous solution (-0.186)^oC. Elevation of boiling point of the same solution is Kb=0.512^oC , Kf = 1.86^C, find the increase in boiling point.
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Answer:
We know ΔTb = mkb and ΔTf = mKf
ΔTb/ΔTf = Kb/Kf
Find ΔTb which would come 0.0512°
Explanation:
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