Frequency of autosomal lethal gene is 0.4. No. of carriers in population of 200 individuals will be
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The frequency of the recessive allele is q = 0.4 (given) Hence, p = 1-0.4 = 0.6 (as p = 1- q) According to Hardy- Weinberg principle, p2 + 2pq + q2 = 1. hnce, p2 = (0.6)2 => 0.36 q2 = (0.4)2 => 0.16 2pq = 0.48 since, 2pq is the frequency of hetrozygous carrier, = 0.48 X 200 => 96 Individuals
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