Question

Frequency of photons having energy of 66ev is

Answer 1

16×10^15Hz  

Solution :

          E=hν

therefore ν=E / h

(66×1.6×10^−19) / (6.6×10^−34)=16×10^15Hz

^ means raise to sign

Answer 2

Frequency (ν) = C/λ (wave length)

= (3*108 meters/sec)/(3000*10-10 meters)

= 1015 sec-1

Energy = hν

= (6.63*10-34 Joule.Sec). 1015 sec-1

Energy = 6.63*10-19 Joule