Friends I have one more doubt. please solve the problem
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i hope this is the right answer
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vijayalakshmi12:
thanque
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ii) In triangles ABO AND ACO
AB=AC (iso. triangles )
AO=OA (common )
ang ABO=ang ACO (angB and angC are the bisectors)
so tri ABO ≅ tri ACO
Therefore ang BAO = ang CAO ( CPCT)
AB=AC (iso. triangles )
AO=OA (common )
ang ABO=ang ACO (angB and angC are the bisectors)
so tri ABO ≅ tri ACO
Therefore ang BAO = ang CAO ( CPCT)
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