Question

Friends please solve the mcq 2 , 3, 4 , 5 in the given question

Answer 1

Answer:

2)  Option c

3) option  (a) 2

4) option (d)

5) option (a) 2 cm

Step-by-step explanation:

2) Option c is the correct answer

18/(2^5 x 3^2x5^7) can be written as

(2 x 3^2) /(2^5 x 3^2x5^7) = 1/(2^4 x 5^7)

If the prime factorization of  denominator  of a fraction is the consists of 2 and  5 then it is a terminating fraction

3)The sum of zeroes of a polynomial  ax^2 + bx + c is  -b/a

Here Kx^2 - 2kx + 3 is the polynomial

-b/a = -(-2k)/k = 2

4)Discriminant of a quadratic equation ax^2 + bx + c is b^2 - 4ac

Here equation be px^2 + qx + r

Discriminant  = q^2 = 4pr

option d is the correct answer

5)In triangle ABC,BC || DE

Then their sides are proportional

AD/AB = AE/AC

1.5/4.5 = 1/AC

AC =2