Math, asked by ANALIYA, 1 month ago

FRIENDS, SOLVE THIS PLZ...!​

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Answers

Answered by CelestialCentrix
3
  1. Scale=1 Div= 15 mins
  2. 210 mins (1Div=15 mins)
  3. 22 kms away(See the Y axis marking Distance (in km))
  4. Between 10:30-11:30
  5. No

 \bold \red{Celestial} \bold{Centerix}

Answered by tennetiraj86
2

Step-by-step explanation:

Solutions :-

a)

The scale on X-axis is 4 cm = 1 hour

=> 1 cm = 1/4 hours

We know that 1 hour = 60 minutes

=> 1 cm = 60/4 minutes

=> 1 cm = 15 minutes

b)

He started on 8 am

He reached on 11:30 am

Time taken for his travelling = 11:30 am - 8 am

= 3:30 hours

=> 3 1/2 hours (or)

=> 7/2 hours (or)

=> (7×60)/2

=> 7×30

=> 210 minutes

c)

The distance from the place of merchant to the town = 22 km

d) He ride fastest in the period of 8 am to 9 am .He travelled 10 km in that period.

e)

Yes , He stopped .

He stopped in the period of 10 am to 10:30 am.after reaching 16 km of travelling

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