Question

The HCF of two numbers is 23 and their LCM is 276. If one of the numbers is 92,
find the other​

Answer 1

Given :

• HCF of two numbers is 23 and their LCM is 276 .
• One of the numbers is 92 .

To Find :

• Other Number .

Solution :

$\longmapsto\tt{Let\:other\:number\:be=x}$

Now ,

$\longmapsto\tt\boxed{Product\:of\:numbers=HCF\times{LCM}}$

$\longmapsto\tt{92\times{x}=23\times{276}}$

$\longmapsto\tt{92\times{x}=6348}$

$\longmapsto\tt{x=\cancel\dfrac{6348}{92}}$

$\longmapsto\tt\bf{x=69}$

So , The other number is 69 .

VERIFICATION :

$\longmapsto\tt{92\times{x}=23\times{276}}$

$\longmapsto\tt{92\times{69}=23\times{276}}$

$\longmapsto\tt\bf{6348=6348}$

HENCE VERIFIED

Answer 2

Answer:

Step-by-step explanation:

Given:-

• The HCF of two numbers is 23 and their LCM is 276. If one of the numbers is 92

To Find:-

• The other number

Solution:-

✇ Let the other number be x

❒ Product of two numbers = HCF ×

LCM

ACQ

➳ 23 × 276 = 92 × x

➳ 92 × x = 23 × 276

➳ x = 23 × 276/92

➳ x = 23 × 3

➳ x = 69

✏ So, Other number = 69