frnds help me ....
i m totaly confused in numericals ....
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Hey friend!!!! Here's your answer!!♥️
Given: a concave lens of focal length 15cm
Distance of image from lens (v)=10cm
To find: distance of object from lens(u)
We know the formula: 1/v - 1/u= 1/f
Since we have v and f we can substitute their value inthe formula
That is :1/15-1/10= -1/u
1/u=1/30
Therefore u=+30cm
Hope it helps you♥️♥️
Always rember the formula and the sign conventions!!
farahalrafeeq:
Sorry I meant to say you are most welcome
Answered by
2
Given,
focal length, f = -15 cm
Distance of image, v = -10 cm
Distance of object, u =?
We know that,
1/v - 1/u = 1/f
So,
1/-10 - 1/u = 1/-15
So, -1/10 + 1/15 = 1/u
(-3 + 2)/30 = 1/u
-1/30 = 1/u
Therefore u = -30 cm
Thus object is placed 30 cm away from the concave lens.
Negative sign shows that object is at 30cm in front of the lens.
Hope this is helpful to you..
Mark as brainlist
focal length, f = -15 cm
Distance of image, v = -10 cm
Distance of object, u =?
We know that,
1/v - 1/u = 1/f
So,
1/-10 - 1/u = 1/-15
So, -1/10 + 1/15 = 1/u
(-3 + 2)/30 = 1/u
-1/30 = 1/u
Therefore u = -30 cm
Thus object is placed 30 cm away from the concave lens.
Negative sign shows that object is at 30cm in front of the lens.
Hope this is helpful to you..
Mark as brainlist
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