frnds pls solve this sum...
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x^a(b-c) / x^b(c-a) = x^ab-ac / x^bc-ab=x^ab-ac-bc+ab=x^2ab-ac-bc
and..
(x^b/x^a)^c= x^bc/x^ac=x^bc-ac
so...
LHS=x^2ab-ac-bc ÷ x^bc-ac
=x^2ab-ac-bc-bc+ac
=x^2ab-2bc
and..
(x^b/x^a)^c= x^bc/x^ac=x^bc-ac
so...
LHS=x^2ab-ac-bc ÷ x^bc-ac
=x^2ab-ac-bc-bc+ac
=x^2ab-2bc
sonam6920:
thank u...
i think question is wrong
thats why my answer is coming wrong
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