If the density of methanol is 0.793kg/L , what is it's volume needed for making 2.5L of its 0.25 M solution ?
Answers
Answered by
27
Molar mass of methanol (CH3OH) = (1×12)+(4×1)+(1×16) = 32 g mol-1 = 0.032 kg mol-1
Molarity of the solution = 0.793/0.032 = 24.78 mol L-1
Applying, M1V1 (Given Solution) = M2V2 (Solution to be prepared)
24.78×V1 = 0.25×2.5 L
V1= 0.02522 L = 25.22 mL
Molarity of the solution = 0.793/0.032 = 24.78 mol L-1
Applying, M1V1 (Given Solution) = M2V2 (Solution to be prepared)
24.78×V1 = 0.25×2.5 L
V1= 0.02522 L = 25.22 mL
9552688731:
Molarity = number of moles of solute/volume of the solution // please tell me how do you take values?
be the mass, then, 0.25 = (x/32) X (1/2.5) = 0.02 Kg
, density = M/ V, the density of methanol is 0.793 KgL-1.
Therefore, Volume = Mass/ Density = 0.02/0.793 = 0.025 Litres
Similar questions
Math,
8 months ago
Economy,
8 months ago
Geography,
1 year ago
World Languages,
1 year ago
Computer Science,
1 year ago
English,
1 year ago
Science,
1 year ago