Question

from 2y^2+3yz+z^2 subtract 2y^2+yz please solve this question ​

Answer 1

Answer:

$4yz + z^{2}$

Step-by-step explanation:

$2y^{2} + yz -2y^{2} + 3yz + z^{2} \\= 2y^{2} -2y^{2}+ yz+ 3yz + z^{2}\\=4yz + z^{2}$

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Answer 2

Answer:

2yz + z²

Step-by-step explanation:

2y² + 3yz + z²

-2y² - yz        

0 + 2yz + z²

= 2yz + z²