Question

from 528 gm of CO2 sample 6.023 × 10^23 atoms of CO2 are removed.find out the moles of CO2 left. Also calculate the mass of sodium which contains same number of atoms as left over in this sample​

Answer 1

Answer:

11 moles of co2 left.

Explanation:

6.023×10^23 atoms = 1 mole

so,

moles of co2= weight/molecular mass

= 528/(12+16× 2)

= 12 moles

6.023×10^23 atoms removed means 1 mole is removed.

= 12-1 mole

= 11 moles..left

for Na,

moles=w/ m

11×(23)=w

253 g is the mass of Na...