Question

From 64 g of ch4,6.023×10^23no of molecules removed how many moles of ch4 left

Answer 1

Answer :

Firstly we will calculate molar mass of CH4

• Atomic mass of Carbon = 12
• Atomic mass of hydrogen = 1

Molar mass of CH4

= 12 + 4

= 16 g

Number of moles = Given mass/molar mass

n = 64g/16g

n = 4 moles

we know that,

number of moles = Given no. of particles/Avogadro's No.

Let the no of particles present in 64 g of CH4 be x

4 = x/6.022 × 10²³

4 × 6.022 × 10²³ = x

x = 24.088 × 10²³ particles are present in 64g of CH4

According to Question :

6.023 × 10²³ no of moles removed then

= 24.088 × 10²³ - 6.023 × 10²³

= 18.065 × 10²³ particles will left

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