From 72 gram of water if 3.01*10^23 molecule are removed than find the no. Of remaining mole of water??
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1 mole of water = 6.02 x 10^23 molecules = 18g
1g has 6.02 x 10^23/18 molecules
72g has 6.02 x 72 x 10^23/18 = 24.08 x 10^23 molecules
no. of molecules removed = 3.01 x 10^23
no .of molecules remaining = (24.08 - 3.01) x 10^23 = 21.07 x 10^23
no. of remaining moles = 21.07 x 10^23/6.02 x 10^23 = 3.5 mol
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