Math, asked by rajdamle48, 3 months ago

From a 9 x 9 x 9 cube, which is formed by
combinations of 1 x 1 x 1 cubes, a layer of the
smaller cubes is removed. What will be the
number of 1 x 1 x 1 cubes present in this new
cube?​

Answers

Answered by krithikasmart11
0

Answer:

343 cubes

Step-by-step explanation:

Given,

A 9 x 9 x 9 cube, which is formed by combinations of 1 x 1 x 1 cubes.

To Find,

Number of 1 x 1 x 1 cubes present in this new cube.

A 9 x 9 x 9 cube has 9 cubes of 1×1×1 cubes along its Length breadth and width each. If we remove a layer of 1×1×1 cubes (the smaller cubes)

Then,

The new cube will have following dimension :

Length=9−1−1 = 7;

Breadth=9−1−1 = 7;

Width=9−1−1 = 7.

So,

The number of 1×1×1 cubes in this = 7 x 7 x 7 = 343

Therefore, the answer is 343 cubes.

#SPJ3

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