Question

from a boat on the river below a dam,the angel of elevation to the top of the angel of elevation to the top of the dam is 24 degree 8' .if the dam is 2039 feet above the level of the level of the river,how far is the boat from the base of the dam (to the nearest foot)

Answer 1

Answer:

Let x be the distance of the boat from the base of the dam.  

The tangent ratio expresses the relationship between the sides of a right triangle depicted above as:  

tanθ=opposite side adjacen tside

tan29∘=2430x

[Substitute the corresponding values]

x=2430(tan29∘)

[Multiply both sides by x/(tan 29deg)]

x≈4384

tanθ=oppositesideadjacentsidetan29∘=2430x[Substitute the corresponding values]x=2430(tan29∘)[Multiply both sides by x/(tan 29deg)]x≈4384

The boat is around 4384 ft away from the base of the dam.

hope it helps you  :)

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Answer 2

Answer:

let you know what you mean by that I have to be done