From a box containing 7 red balls ,5 green balls and 3 blue balls. 3 balls are drawn one after the other. What is the probability of drawing red ball in the first draw, blue ball in the second draw and green ball in the 3rd draw ?
If ball is not replaced back after each draw
Answers
Answered by
5
Answer:
Red ball=4/15
Green Ball=2/15
Blue Ball=0
Answered by
1
Answer:
Red ball=7
Green ball=5
Blue ball=3
Total balls=15
Step-by-step explanation:
P(Drawing a red ball)=No. of Favourable outcomes/Total outcomes
= 7/15
P(Drawing a blue ball)=No. of Favourable outcomes/Total outcomes
= 3/14
P(Drawing a ball)=No. of Favourable outcomes/Total outcomes
=5/13
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