Math, asked by shivamchandel711, 5 months ago

From a box containing 7 red balls ,5 green balls and 3 blue balls. 3 balls are drawn one after the other. What is the probability of drawing red ball in the first draw, blue ball in the second draw and green ball in the 3rd draw ?

If ball is not replaced back after each draw​

Answers

Answered by ansumanhazarika90
5

Answer:

Red ball=4/15

Green Ball=2/15

Blue Ball=0

Answered by arpitafelix6040
1

Answer:

Red ball=7

Green ball=5

Blue ball=3

Total balls=15

Step-by-step explanation:

P(Drawing a red ball)=No. of Favourable outcomes/Total outcomes

= 7/15

P(Drawing a blue ball)=No. of Favourable outcomes/Total outcomes

= 3/14

P(Drawing a ball)=No. of Favourable outcomes/Total outcomes

=5/13

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