The sides of a triangle are in the ratio 12:17:25 and it's perimeter is 540 cm find its area class9 exercise 12.1 question number 5 please if you know the answer so please tell plz plz
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Answer:
12x+17x+25x=540
54x=540
x=540/54=10
12x =12×10=120
17x=17×10=170
25x=25×10=250
s=perimeter/2=540/2=270
By heron's formula
area of triangle=√(s(s-a)(s-b)(s-c))
=√(270(270-120)(270-170)(270-250))
=√(270(150)(100)(20))
=√81,000,000
=9,000 cm²
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Answered by
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Answer:
9000cm²
Step-by-step explanation:
Suppose common ratio btwn sides of triangle = a
So, sides are 12a,17a,25a.
Perimeter =540
12a+17a+25a=540
a=10
Then, sides are 120,170,250.
S=Perimeter /2=540/2=270
Area of triangle =√¯¯¯¯¯¯¯¯¯¯s(s-a) (s-b) (s-c)
Substitute the values..
Area =9000 cm²
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