Math, asked by sonivishalvs6291423, 5 months ago

From a building 60 m high the angle of depression of the top and bottom of lamp

are 300

and 600

respectively. Find the distance between lamp post and building.

Also find the difference of height between building & lamp post.​

Answers

Answered by muskanjain2510
1

Answer:

Consider the given data.

Consider the given data.The height of building AB=60 m.

Consider the given data.The height of building AB=60 m. 

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure.

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x60

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m 

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m 

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m Therefore,

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m Therefore,The distance of between AB and CD is 360 m.

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m Therefore,The distance of between AB and CD is 360 m.The height of lamp post is 40 m.

Consider the given data.The height of building AB=60 m. And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30∘ and  60∘, respectively shown in the figure. In the △ADB,tan60∘=x603=x60x=360 m In the △ACP,  tan30∘=x60−h 31=36060−h 360=60−h h=60−20h=40 m Therefore,The distance of between AB and CD is 360 m.The height of lamp post is 40 m.The difference between the height of the building and the lamp post =60−40=20 m

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