From a building two balls A and B are thrown such that A is thrown upwards and B downwards (both vertically). If y, and vg are their respective velocities on reaching the ground, then
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Let the ball A is thrown vertically upwards with speed u and ball B is thrown vertically downwards with the same speed u. After reaching the highest point, After reaching the highest point,A comes back to its point of projection with the same speed u in the downward direction. If h be the height of the building,then the velocity of A on reaching the ground is
- (vA)² = u² + 2gh
- is (vB)² = u² + 2gh
(vA)² = (vB)²
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