Question

From a circle of radius 15 cm, a sector with angle 216° is cut out and its bounding radi
are bent so as to form a cone. Find its volume
​

Answer 1

Answer:

Here , the cone radius is 15cm

height=radius

Step-by-step explanation:

$volume \: of \: cone = \pi \: {r}^{2 } \frac{h}{3}$

$\pi = \frac{22}{7}$

22/7×(15)² ×15/3

22/7×225×5

22/7×1125

3534.29173529cm³

Answer 2

Step-by-step explanation:

Radius of the circle = R = 15 cm. angle of the sector = 216°.

Length of the circular arc cut off from the

circle

2 TR . 9/360°

= 2 .22/7 . 15 .216/360 cm

= 396/7 cm

The piece is bent into a right circular

cone.

So the slanting height s of the cone = radius of circle = R = 15 cm.

s = 15 cm

circumference of the base of the cone = arc length 396/7 cm

base radius r of the cone = r = 396 /7

1/2 π = 9 cm

height of the cone = h = v(s^2 - r^2) = 15^2 -

9^2 = 12 cm

Volume of the cone = V = TT/3 r2 h = V = 22/7 1/3 . 9^2 . 12 cm3

= 7128/7 cm3