Question

From a circular card sheet of a radius 14 to circle of the radius 3.5 cm and a rectangle of length 3 cm and breadth ones are removed as shown in the adjoining figure find the area of the remaining sheet Pi is equal to 22 by 7

Answer 1

Explanation:

Radius of circular card sheet = 14 cm

Area of circular card sheet = πr² = 22/7×14×14

= 616 cm²

Radius of smaller circle = 3.5 cm

Area of smaller circle = πr² = 22/7×3.5×3.5

38.5 cm²

Area of rectangle with 3 cm length and 1 cm breadth = length × breadth = 3 × 1 = 3 cm²

Area of circular card sheet remaining = 616 - (3+38.5) = 616 - 41.5 = 574.5 cm²

Answer 2

$\large{\bf{\blue{\underline{\underline{Hi....!! }}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$