from a circular card sheet of radius 14 cm , two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 2 cm are removed . find the area of remaining sheet .
Answers
Answer:
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR
2
−[2(πr
2
)+(l×b)]
=
7
22
×14×14−[(2×
7
22
×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm
2
Therefore the area of remaining sheet is 536cm
2
.
Step-by-step explanation:
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Step-by-step explanation:
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR
2
−[2(πr
2
)+(l×b)]
=
7
22
×14×14−[(2×
7
22
×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm
2
Therefore the area of remaining sheet is 536cm
2
.