Question

From a circular card sheet of radius 14cm, two circles of radius 3.5 cm and a rectangle of length 3cm and breadth 1 cm are removed. Find the area of the remaining sheet.

Answer 1

radius of circular sheet=14cm
area of circular sheet=πr²
=22/7*14*14
=616cm²

radius of circle to be cut= 3.5 cm
area of the circle= πr²
=22/7*3.5*3.5
=5.5 cm²

as there are 2 circles to be cut,
area of circles= 2*5.5cm²
=11cm²

length of rectangle=3cm
breath of rectangle=1cm
area of rectangle= 3cm²

total area of sheet to be cut= (11+3)cm²
=14cm²


area of sheet left= (616-14)cm²
=602cm²


So your answer is 602cm²


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Answer 2

$\large{\bf{\green{\underline{\underline{♧.AnsWer.♧}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$